Model
An ideal four-level medium of length lg sits in a linear cavity of length L between mirrors R1, R2.
One cavity mode of area A holds q photons, and N atoms are inverted. In the uniform-field (mean-field) approximation:
- N
- number of inverted atoms in the mode volume (four-level: N = N2)
- q
- photons in the lasing mode, both directions together
- Rp
- pump rate into the upper level, Rp = Pp/hνp (s⁻¹)
- τ, τp
- upper-state lifetime and photon (cavity) lifetime
- σ, A, β
- emission cross-section, mode area, spontaneous-emission fraction into the mode
- g, α
- single-pass intensity gain coefficient σN/(Alg) and internal loss (m⁻¹)
- δ
- logarithmic round-trip loss, so photons decay as e−δ per round trip
- r
- pump ratio Rp/Rp,th
- T2
- output-coupler transmission 1 − R2 (lossless mirror)
Assumptions and validity: ideal four-level medium with instant pump-band and lower-level decay, a single mode, the uniform-field limit (small loss per pass, δ ≲ 0.3), unit pump quantum efficiency, group index 1, and no spatial hole burning, thermal lensing or reabsorption. Numerics: fixed-step RK4 with Δt = min(τp/10, τ/1000). Halving Δt changes the transient by less than 10⁻⁴. The pump sweep uses Δt = τp/2, which is allowed because RK4's fixed points are the exact equilibria of the ODE.
Derivation: threshold, photon lifetime and the L–I line
Over one round trip the intensity is multiplied by M = R1R2e2glge−2αL. Spreading that change evenly over Trt gives a photon growth rate ln M/Trt = 2glg/Trt − δ/Trt. With g = σN/(Alg), the first term is 2σN/(A Trt) = cσN/(AL) = GN, and the second is 1/τp. So the photon equation is exactly dq/dt = (GN − 1/τp)q, and threshold GN = 1/τp is the same as M = 1.
In steady state above threshold, dq/dt = 0 with q ≫ 1 forces GN = 1/τp. The inversion, and hence the gain, is clamped at Nth. Then dN/dt = 0 gives Rp − Nth/τ = GNthq = q/τp, so q = τp(Rp − Rp,th). Every photon hits the output coupler once per round trip, so Pcirc = q hν/Trt and Pout = T2Pcirc = (T2/δ)(hν/hνp)(Pp − Pp,th). The slope ηs is the output-coupling efficiency T2/δ times the quantum defect λp/λ.
Exact bookkeeping. The photon loss rate q/τp = qδ/Trt splits between the output mirror, the back mirror and internal loss in the ratio ln(1/R2) : ln(1/R1) : 2αL. With the "exact photon budget" option, Pout = ln(1/R2) q hν/Trt, and absorbed pump photons = spontaneous decays + output + back mirror + internal loss holds exactly. Since ln(1/R2) = T2 + T2²/2 + …, the two options differ by about T2/2 (2.5 % at R2 = 95 %).
Relaxation oscillations. Write N = Nth + n and q = q0 + m, drop the products nm, and set β → 0. This gives dn/dt = −(r/τ)n − m/τp and dm/dt = Gq0n = ((r−1)/τ)n. Eliminating n gives m̈ + (r/τ)ṁ + (r−1)/(ττp) m = 0, a damped oscillator with ω0² = (r−1)/(ττp) and γR = r/(2τ). Because τp ≪ τ, the oscillation is strongly underdamped for any r that is not extremely close to 1.
Worked example: a diode-pumped Nd:YAG laser
Take L = 10 cm, lg = 5 cm, R1 = 99.8 %, R2 = 95 %, α = 0.2 m⁻¹, σ = 2.8×10⁻²³ m², τ = 230 µs, w = 0.5 mm and Pp = 2.80 W at 808 nm. Find the threshold, output power and relaxation frequency.
- Round-trip loss: δ = ln(1/0.998) + ln(1/0.95) + 2(0.2)(0.1) = 0.0020 + 0.0513 + 0.0400 = 0.0933. Trt = 2L/c = 0.667 ns, so τp = Trt/δ = 7.15 ns.
- Threshold gain: gth = δ/(2lg) = 0.933 m⁻¹. With A = πw² = 7.85×10⁻⁷ m², G = cσ/(AL) = 1.07×10⁻⁷ s⁻¹ and Nth = 1/(Gτp) = 1.31×10¹⁵ atoms.
- Threshold pump: Rp,th = Nth/τ = 5.69×10¹⁸ s⁻¹, and hνp = 2.46×10⁻¹⁹ J gives Pp,th = 1.40 W. The pump ratio is r = 2.00.
- Slope and output: ηs = (808/1064)(0.05/0.0933) = 0.407, so Pout = 0.407 × (2.80 − 1.40) = 0.569 W and Pcirc = Pout/T2 = 11.4 W.
- Relaxation: γR = r/(2τ) = 4.35×10³ s⁻¹ (1/e time 230 µs), and ωR ≈ √((r−1)/(ττp)) = 7.80×10⁵ s⁻¹, so fR = 124 kHz. The simulator's kicked response gives the same value to better than 10⁻⁴.
Load "2 × threshold" and check each number against the readouts.